Integrand size = 41, antiderivative size = 75 \[ \int \frac {1}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}} \sqrt {a^2+b^2 x}} \, dx=-\frac {2 \sqrt {a^2-b^2 x} \arctan \left (\frac {\sqrt {a^2-b^2 x}}{\sqrt {a^2+b^2 x}}\right )}{b^2 \sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}}} \]
[Out]
Time = 0.04 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.098, Rules used = {533, 65, 223, 209} \[ \int \frac {1}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}} \sqrt {a^2+b^2 x}} \, dx=-\frac {2 \sqrt {a^2-b^2 x} \arctan \left (\frac {\sqrt {a^2-b^2 x}}{\sqrt {a^2+b^2 x}}\right )}{b^2 \sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}}} \]
[In]
[Out]
Rule 65
Rule 209
Rule 223
Rule 533
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2-b^2 x} \int \frac {1}{\sqrt {a^2-b^2 x} \sqrt {a^2+b^2 x}} \, dx}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}}} \\ & = -\frac {\left (2 \sqrt {a^2-b^2 x}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {2 a^2-x^2}} \, dx,x,\sqrt {a^2-b^2 x}\right )}{b^2 \sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}}} \\ & = -\frac {\left (2 \sqrt {a^2-b^2 x}\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt {a^2-b^2 x}}{\sqrt {a^2+b^2 x}}\right )}{b^2 \sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}}} \\ & = -\frac {2 \sqrt {a^2-b^2 x} \tan ^{-1}\left (\frac {\sqrt {a^2-b^2 x}}{\sqrt {a^2+b^2 x}}\right )}{b^2 \sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}}} \\ \end{align*}
Time = 10.04 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00 \[ \int \frac {1}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}} \sqrt {a^2+b^2 x}} \, dx=-\frac {2 \sqrt {a^2-b^2 x} \arctan \left (\frac {\sqrt {a^2-b^2 x}}{\sqrt {a^2+b^2 x}}\right )}{b^2 \sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}}} \]
[In]
[Out]
\[\int \frac {1}{\sqrt {b^{2} x +a^{2}}\, \sqrt {a -b \sqrt {x}}\, \sqrt {a +b \sqrt {x}}}d x\]
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.67 \[ \int \frac {1}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}} \sqrt {a^2+b^2 x}} \, dx=-\frac {2 \, \arctan \left (-\frac {a^{2} - \sqrt {b^{2} x + a^{2}} \sqrt {b \sqrt {x} + a} \sqrt {-b \sqrt {x} + a}}{b^{2} x}\right )}{b^{2}} \]
[In]
[Out]
\[ \int \frac {1}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}} \sqrt {a^2+b^2 x}} \, dx=\int \frac {1}{\sqrt {a - b \sqrt {x}} \sqrt {a + b \sqrt {x}} \sqrt {a^{2} + b^{2} x}}\, dx \]
[In]
[Out]
\[ \int \frac {1}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}} \sqrt {a^2+b^2 x}} \, dx=\int { \frac {1}{\sqrt {b^{2} x + a^{2}} \sqrt {b \sqrt {x} + a} \sqrt {-b \sqrt {x} + a}} \,d x } \]
[In]
[Out]
\[ \int \frac {1}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}} \sqrt {a^2+b^2 x}} \, dx=\int { \frac {1}{\sqrt {b^{2} x + a^{2}} \sqrt {b \sqrt {x} + a} \sqrt {-b \sqrt {x} + a}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {1}{\sqrt {a-b \sqrt {x}} \sqrt {a+b \sqrt {x}} \sqrt {a^2+b^2 x}} \, dx=\int \frac {1}{\sqrt {a+b\,\sqrt {x}}\,\sqrt {a-b\,\sqrt {x}}\,\sqrt {a^2+x\,b^2}} \,d x \]
[In]
[Out]